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- Select your device by clicking its icon on the toolbar at the upper left corner of the iTunes window. Click the “Summary” heading in the sidebar and then click the “Check for Update” button under the device’s name in the main pane. ITunes will check for any available updates and prompt you to install them.
- Added keyboard shortcut (speed) 4. Added OSD (On-screen display) feature. Drag & Drop is available while video is playing. Application is available to move while video is playing.
Hi Shelly,
I like this problem a lot partly because there are so many ways to solve it. If your son knows some algebra he can solve it using the algebraic technique used on the algebra.com web site.
This problem can however be presented to a student as soon as he or she learns to do arithmetic with decimals. I think this is wonderful problem to give to a group of such students and have them work on a joint solution. I am going to use the numeric values in the problem referred to above and refer to the three chickens as a rooster, a hen and a chick with the rooster the heaviest and the chick the lightest.
The rooster and the chick weigh 8.5 kg and the hen and chick weigh 6.1 kg. Thus the rooster weighs 8.5 - 6.1 = 2.4 kg more than the chicken. But the rooster and the hen together weigh 10.6 kg. Hence, on the scale with the rooster and the hen replace the rooster by an identical hen and a 2.4 kg weight. The scale will still read 10.6 kg. Remove the 2.4 kg weight and the scale reads 10.6 - 2.4 = 8.2 kg. Thus two chickens weigh 8.2 kg. What does one chicken weigh?
A third solution comes from an observation. What does 10.6 + 8.5 + 6.1 = 25.2 kg represent in terms of roosters, hens and chicks?
I hope this helps,
Penny
I think I might know what you mean, and if so, it's not a ratio problem but a problem in linear algebra.
Are the data in a form like:
Qq 10.6.8 Version
X and Y together weigh A
Y and Z together weigh B
Z and X together weigh C ?
This gives rise to the linear equation system
Qq 10.6.8 Mac
x + y = A
y + z = B
x + z = C
This isn't in triangular form, so has no obvious 'weak spot.' But you can (for instance) subtract the second equation from the first to get a second equation in x and z; then add this to the third to eliminate z.
Q106.8
Good Hunting!
RD